The cheapest cities in the world for 5* hotels have been revealed in new research – Bangkok, Thailand is the 3rd cheapest city in the world offering five-star luxury for $108.
The research from Luxury Hotel analysed the cost of a one night stay at five-star hotels across the world to reveal the cheapest cities in the world for a night of luxury.
You can view the research in full here: https://luxuryhotel.com/
The 10 cheapest cities in the world for five-star hotels
|
Rank |
City |
Price per night in 5* hotel |
|
1 |
Kuala Lumpur, Malaysia |
$94 |
|
2 |
Ho Cho Minh City, Vietnam |
$104 |
|
3 |
Bangkok, Thailand |
$108 |
|
4 |
Antalya, Turkey |
$108 |
|
5 |
Mexico City, Mexico |
$118 |
|
6 |
Sapporo, Japan |
$118 |
|
7 |
Hanoi, Vietnam |
$118 |
|
8 |
Phuket, Thailand |
$120 |
|
9 |
Chiang Mai, Thailand |
$123 |
|
10 |
Mecca, Saudi Arabia |
$134 |
Bangkok, Thailand is the 3rd cheapest city in the world for five-star hotels, with a price of $108 per night. 8 of the 10 cheapest places for five-star hotels are in Asia, one in each of Europe and North America.
Further findings:
-
The global average of a one night stay in a five-star hotel is $272, in comparison, Europe’s average is $286.
-
Mexico City, Mexico, is North America’s cheapest five-star destination costing $118. It was followed by Punta Cana, Dominican Republic ($246) and Las Vegas, USA ($273).
-
Doha, Qatar has the highest proportion of five-star hotels, with 51.43% of its hotels being five-star. New York has the highest proportion of five-star hotels in the US, with 14.22%.
You can view the research, including the city’s with the most five-star hotels, in full here: https://luxuryhotel.com/
